Rob Gronkowski returns to Buccaneers in NFL free agency

Rob Gronkowski isn’t going anywhere.

The star tight end on Monday agreed to a one-year, $10 million contract to remain with Tom Brady and the Tampa Bay Buccaneers, according to ESPN.

Gronkowski, 31, recently suggested he could leave the Buccaneers in NFL free agency.

“I definitely want to be back with the Buccaneers. That’s where my eyesight is. That’s where I’m leaning toward, big time,” Gronkowski said on the 10 Questions with Kyle Brandt podcast. “But with the free agency process, you just never know what may happen. There’s some other teams interested out there, too. I’ve also never been a part of the free-agency process, so I actually want to dip my toes in, just to see what’s out there.”

The future Hall of Famer and four-time champion came out of retirement before last season and progressively improved throughout the year.

Gronkowski caught 45 passes for 623 yards and seven touchdowns in 2020 and added two receiving touchdowns in the Buccaneers’ Super Bowl win over the Chiefs.

Brady, who last week signed an extension with Tampa, is the only quarterback Gronkowski has played with, as the two now will chase back-to-back titles.